NBA Slam Dunk Contest Odds

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HOUSTON, TX (TheSpread) – The featured event of NBA All-Star Saturday Night is the 2013 Sprite Slam-Dunk Contest. Here is a look at the odds to win this year’s contest.

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According to oddsmakers at Bovada.lv, New York’s James White is the favorite to win, as he has 5/4 odds to win. Other short odds to win are Toronto’s Terrence Ross (7/2) and Indiana’s Gerald Green (4/1). The defending champion, Jeremy Evans of Utah, surprisingly has 8/1 odds to win.

White has not done much on the court this season, scoring just 1.8 points per game. However, he is known for being quite the high flyer and had some spectacular dunks in an international dunk contest in the past. White is 6-7. The Knicks have had four former Slam Dunk champions, with the last being Nate Robinson in 2010.

Ross is a decent contributor for Toronto, as he averages 6.4 points per game. He stands 6-6 and has plenty of leaping ability. The Raptors have only had one Slam Dunk champion, and that was Vince Carter in 2000.

Green is a former winner, as he took the 2007 title as a member of the Boston Celtics. Green stands 6-8 and averages 6.6 points per game this season. The Pacers have claimed one Slam Dunk title. That was Fred Jones in 2004.

Bet on NBA All-Star Weekend Odds

The dunk contest will be part of NBA All-Star Saturday Night, this Saturday, at 7PM ET from the Toyota Center in Houston. The event will air live on TNT. For the odds for each competitor to win this year’s NBA Sprite Slam-Dunk Contest, see below.

2013 NBA Sprite Slam-Dunk Contest Odds

James White (NYK) 5/4 

Terrence Ross (TOR) 7/2 

Gerald Green (IND) 4/1 

Eric Bledsoe (LAC) 5/1 

Jeremy Evans (UTA) 8/1 

Kenneth Faried (DEN) 8/1 

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